How do you express ${log}_{2} 13$ $log_2 13$ in terms of common logarithms?

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Answer 1 · 2016-11-15T23:40:07

${log}_{2} (13) = \frac{{log}_{10} (13)}{{log}_{10} (2)} = \frac{ln (13)}{ln (2)}$ $log_2(13) = log_10(13)/log_10(2) = ln(13)/ln(2)$

Use the property of all logarithms:

${log}_{c} (a) = \frac{{log}_{b} (a)}{{log}_{b} (c)}$ $log_c(a) = log_b(a)/log_b(c)$

How do you express log213log_2 13 in terms of common logarithms?