How do you solve $log_9 (3x)+log_9 2 =2$ ?

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Answer 1 · 2016-07-19T05:44:42

$x=13.5$

$log_9(3x)+log_9(2)=2$

$hArrlog_9(3x×2)=2$

$hArr3x×2=9^2$ or

$6x=81$ i.e.

$x=81/6=27/2=13.5$

How do you solve log_9 (3x)+log_9 2 =2log_9 (3x)+log_9 2 =2?