How do you simplify $5^[log_5 (6) + log_5 (7)]$ ?

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Answer 1 · 2016-03-20T11:37:32

42

The operation $(a^(log_a))$ is successively an operation and its inverse operation. This is equivalent to multiplication by 1.

So, $a^(log_a x) =x$ .
Also, log a + log b = log (ab)

Here, $5^(log_5(6)+log_5(7))=5^(log_5(42))=42$ .

How do you simplify 5^[log_5 (6) + log_5 (7)]5^[log_5 (6) + log_5 (7)]?