How do you calculate $log_(1/5) 125$ ?

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Answer 1 · 2016-04-18T01:59:58

First, use the change of base rule $log_an = logn/loga$

$log_(1/5)(125)$

$->log125/log(1/5)$

$->log(5^3)/log(5^-1)$

Now, use the following log rule: $logn^a = alogn$

$->(3log5)/(-1log5)$

$->-3$

Thus, $log_(1/5)(125) = -3$

Hopefully this helps!

How do you calculate log_(1/5) 125log_(1/5) 125?