Question

How do you solve `4^(5n)>30`?

Answer 1

`n>0.49`

Explanation:

By rules of logarithms:

`lna^b=blna`

Therefore, take the logarithm from both sides of the function and follow the rule. Then proceed to rearrange and simplify to find the solution for `n`.

`ln4^5n>ln30`

`5nln4>ln30`

`5n>ln30/ln4`

`n>(ln30/ln4)/5`

`n>0.49`

Hope this helps!