How do you evaluate $log_(3) 2 times log_(2) 27$ ?

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Answer 1 · 2016-04-20T18:01:21

I found $3$

We can try changing base of the second to write:
$log_3(2)xx(log_3(27))/(log_3(2))=$
$=cancel(log_3(2))xx(log_3(27))/cancel((log_3(2)))=log_3(27)=3$

How do you evaluate log_(3) 2 times log_(2) 27log_(3) 2 times log_(2) 27?