How do you expand $log (6*11)$ ?

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Answer 1 · 2018-07-14T15:43:00

$log6+log11$

The key realization is that we can leverage the logarithm property

$log(ab)=loga+logb$

In our example, our $a=6$ and $b=11$ , so we can expand this as

$log6+log11$

Hope this helps!

How do you expand log (6*11)log (6*11)?