How do you use the properties of logarithms to expand $log_4 (5x)$ ?

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Answer 1 · 2017-10-30T12:30:26

$log_4 (5x) =1.16+log_4 x$

$log_4 (5x) = log_4 5 +log_4 x= log5/log4 + log_4 x$

$= 1.16(2dp)+log_4 x$

Properties used are :
$log_a (xy) = log x + log y and log_a x = log_10 x/log_10 a$

$log_4 (5x) =1.16+log_4 x$ [Ans]

How do you use the properties of logarithms to expand log_4 (5x)log_4 (5x)?