How do you condense $1/3log 3x + 2/3log 3x$ ?

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Answer 1 · 2016-03-22T20:37:01

$1/3 log 3x + 2/3 log 3x$ $=log(3x)$

$1/3 log 3x + 2/3 log 3x$

$= log(3x)^(1/3) + log(3x)^(2/3)$ -> use property $log_bx ^n = nlog _b x$

$=log((3x)^(1/3) (3x)^(2/3))$ -> use property $log_b(xy)=log_bx+log_by$

$=log((3x)^(1/3+2/3))$ -> use property $x^a*x^b=x^(a+b)$

$=log(3x)$

How do you condense 1/3log 3x + 2/3log 3x 1/3log 3x + 2/3log 3x ?