How do you find the inverse of #log(x)=3#?

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Answer 1 · 2016-11-18T04:48:42

Please see the explanation.

I am assuming that the logarithm is base 10:

#log_10(x) = 3#

Make both sides of the equation an exponent of 10:

#10^(log_10(x)) = 10^3#

Use the property of logarithms, #b^(log_b(x)) = x#:

#x = 10^3#

#x = 1000#