How do you evaluate ${log 10}^{- 2}$ $log10^-2$ ?

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How do you evaluate ${log 10}^{- 2}$ $log10^-2$ ?

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Answer 1 · 2016-03-18T16:59:30

I found $- 2$ $-2$ if in base $10$ $10$ .

Explanation:

We can take the $- 2$ $-2$ and put it in front of the log:
${log 10}^{- 2} = - 2 log 10 =$ $log10^(-2)=-2log10=$
if your log is in base $10$ $10$ you then get (from the definition of log):
$= - 2 \cdot 1 = - 2$ $=-2*1=-2$

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How do you evaluate ${log 10}^{- 2}$ $log10^-2$ ?

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