How do you calculate $log_2 8^2$ ?

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Answer 1 · 2016-04-14T08:35:35

$log_2(8^2)=6$

$log_2(8^2)$ can be written as

$log_2((2^3)^2)$

= $log_2(2^6)=6log_2(2)=6*1=6$

How do you calculate log_2 8^2 log_2 8^2 ?