How do you evaluate $log_10 200 - log_10 2$ ?

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Answer 1 · 2016-03-27T18:06:07

$2$

From the laws of logs we have that

$log_ax-log_ay=log_a(x/y)$

So in this particular case we get that

$log_10 200-log_10 2 = log_10 (200/2)$

$=log_10 100$

$=2$ . (since $10^2=100$ )

How do you evaluate log_10 200 - log_10 2 log_10 200 - log_10 2?