How do you solve $2^{3 x} = 32$ $2^(3x) = 32$ ?

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Answer 1 · 2016-05-15T21:14:20

$x = \frac{5}{3}$ $x = 5/3$

$32 = 2^{5} = 2^{3 x}$ $32 = 2^5 = 2^(3x)$
then equating the exponents
$5 = 3 x \to x = \frac{5}{3}$ $5=3x-> x=5/3$

How do you solve 2^(3x) = 3223x=322^(3x) = 32?