How do you solve $log (10 - 4 x) = log (10 - 3 x)$ $log (10-4x)=log(10-3x)$ ?

Question

How do you solve $log (10 - 4 x) = log (10 - 3 x)$ $log (10-4x)=log(10-3x)$ ?

1 Answer

Impact of this question

5407 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-14T08:01:56

x = 0

Explanation:

Making use of the following fact from $laws of logarithms$ $color(blue)"laws of logarithms"$

$color(red)(|bar(ul(color(white)(a/a)color(black)(logx=logyrArrx=y)color(white)(a/a)|)))$

$rArr10-4x=10-3xrArrx=0$

Science

Math

Humanities

... and beyond

How do you solve $log (10 - 4 x) = log (10 - 3 x)$ $log (10-4x)=log(10-3x)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve log (10-4x)=log(10-3x)log(10−4x)=log(10−3x)log (10-4x)=log(10-3x)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $log (10 - 4 x) = log (10 - 3 x)$ $log (10-4x)=log(10-3x)$ ?