How do you simplify $log_(5) (1/15)$ ?

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Answer 1 · 2016-06-12T01:15:11

$=log_5(1) - log_5(15)$

Consider that $log(1)$ of anything is equal to $0$ .

$=0 - log_5(15)$

$=-log_5(5 xx 3)$

Recall that $log(a xx n) = loga + logn$

$= -(log_5(5) + log_5(3))$

Finally, remember that $log_a(a) = 1$ .

$= -log_5(3) - 1$

Hopefully this helps!

How do you simplify log_(5) (1/15) log_(5) (1/15)?