How do you calculate ${log}_{\frac{1}{2}} 4$ $log_(1/2) 4$ ?

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Answer 1 · 2016-05-14T04:40:00

$- 2$ $-2$

For long-term-memory: #log_b a=.log_c a/log_c b=log a/log b=ln a/

Here, ${log}_{\frac{1}{2}} 4$ $log_(1/2) 4$

$= \frac{log 4}{log (\frac{1}{2})}$ $= log 4/log (1/2)$

$= \frac{{log 2}^{2}}{- log 2}$ $=log 2^2/(-log 2)$
$= - 2 \frac{log 2}{log 2} = - 2$ $=-2 log 2/log 2=-2$ #

How do you calculate log_(1/2) 4log124log_(1/2) 4?