How do you calculate $8^(2/log 2)$ ?

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Answer 1 · 2018-07-17T19:46:29

$8^{2/{\log 2}}=10^6$

Given that

$8^{2/{\log 2}}$

$=(2^3)^{2/{\log 2}}$

$=2^{6/{\log 2}}$

$=2^{6\log_2(10)}$

$=2^{\log_2(10^6)}$

$=10^6$

How do you calculate 8^(2/log 2) 8^(2/log 2) ?