How do you simplify 10^(log sqrt x )10logx?

1 Answer
Aug 30, 2016

sqrtxx
(Assuming log = log_10log=log10)

Explanation:

Consider: a=10^b -> log_10 a =ba=10blog10a=b

In this example: y = 10^(log_10sqrtx)y=10log10x

So, a=ya=y and b=log_10 sqrtxb=log10x in this case

:. log_10 y = log_10 sqrt(x)

Hence y=sqrtx