How do you condense $log (x + 2) - log x$ $log (x+2) - log x$ ?

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Answer 1 · 2016-06-22T21:53:51

$log (\frac{x + 2}{x})$ $log((x+2)/x)$

To condense $log (x + 2) - log x$ $log(x+2)-logx$

Eliminate the subtraction by dividing the value

$log (\frac{x + 2}{x})$ $log((x+2)/x)$

How do you condense log (x+2) - log x log(x+2)−logxlog (x+2) - log x ?