Question

How do you condense `log_6 25 - log_6 5`?

Answer 1

Since the log's are in the same base, you can immediately condense using the rule `log_an - log_am = log_a(n/m)`

Explanation:

`log_6(25) - log_6(5) = log_6(25/5) = log_6(5)`

Practice exercises:

1. Condense `log_5(x + 4) + log_5(2x - 1)`

Challenge problem:

Using the log rule `log_a(n) = (logn)/(loga)` and the multiplication/division rules shown earlier simplify the following expression completely.

`log_2(20) - log_4(5)`

Hopefully this helps!