How do you calculate ${log}_{\frac{1}{125}} 125$ $log_(1/125) 125$ ?

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Answer 1 · 2016-04-08T17:31:01

$x = - 1$ $x=-1$

${log}_{\frac{1}{125}} 125 = x$ $log_(1/125) 125=x$

$125 = {(\frac{1}{125})}^{x}$ $125=(1/125)^x$

$5^{3} = {(5^{- 3})}^{x}$ $5^3=(5^-3)^x$

$5^{3} = 5^{- 3 x}$ $5^3=5^(-3x)$

$so equation has the same base;$ $"so equation has the same base;"$

$3 = - 3 x$ $3=-3x$

$x = - 1$ $x=-1$

How do you calculate log_(1/125) 125log1125125log_(1/125) 125?