How do you simplify 4^(log_2 [log_ 2(x^2+24x))]?

1 Answer
Jun 17, 2016

This is the best I got:

Explanation:

I tried writing 4 as 2*2:
(2*2)^(log_2[log_2(x^2+24x)])=2^(log_2[log_2(x^2+24x)])*2^(log_2[log_2(x^2+24x)])=
And:
=cancel(2)^(cancel(log_2)[log_2(x^2+24x)])*cancel(2)^(cancel(log_2)[log_2(x^2+24x)])=
=log_2(x^2+24x)log_2(x^2+24x)