How do you simplify $3 log_b m – 2 log_b n$ ?

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Answer 1 · 2016-03-07T09:16:52

$log_bm^3-log_bn^2=log_b(m^3/n^2)$

Use properties of logarithm $log_ab^x=x*log_ab$ and $log_ab-log_ac =log_a(b/c)$ to simplify.

How do you simplify 3 log_b m – 2 log_b n3 log_b m – 2 log_b n?