How do you condense $(1/2)log x - 5 log y - log z$ ?

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Answer 1 · 2016-06-25T08:04:23

$logx^(1/2)/(y^5z)$

Use the power law first:

$logx^(1/2) - logy^5 - logz$

If the logs are being subtracted, then the values were being divided.

Write as a log of a single term: $logx^(1/2)/(y^5z)$

How do you condense (1/2)log x - 5 log y - log z (1/2)log x - 5 log y - log z ?