Question

How do you condense `log_(6)(x+4)+1/2log_(6)x`?

Answer 1

`log_6((x+4)sqrtx)`

Explanation:

Since `n log_b a=log_b a^n`, you have

`1/2log_6 x=log_6 x^(1/2)=log_6sqrt(x)`

Since `log_b a+log_b c=log_b (ac)`, you have

`log_6(x+4)+log_6sqrtx=log_6((x+4)sqrtx)`