How do you condense $log_3 (9x^4)-log_3(3x)^2$ ?

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Answer 1 · 2016-10-11T00:28:43

Start by expanding $log_3(3x)^2$

$log_3(3x)^2 = log_3(9x^2)$

$=>log_3(9x^4) - log_3(9x^2)$

$=> log_3((9x^4)/(9x^2))$

$=>log_3(x^2)$

Hopefully this helps!

How do you condense log_3 (9x^4)-log_3(3x)^2log_3 (9x^4)-log_3(3x)^2?