How do you condense $3 log (x) + log (4)$ $3log(x)+log(4)$ ?

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How do you condense $3 log (x) + log (4)$ $3log(x)+log(4)$ ?

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Answer 1 · 2016-03-22T19:52:32

$3 log x + log 4$ $3logx+log4$ $= log (4 x^{3})$ $=log(4x^3)$

Explanation:

$3 log x + log 4$ $3logx+log4$
$= {log x}^{3} + log 4$ $=logx^3+log4$ ->use property ${log}_{b} x^{n} = n \cdot {log}_{b} x$ $log_bx^n=n*log_bx$
$= log (4 x^{3})$ $=log(4x^3)$

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How do you condense $3 log (x) + log (4)$ $3log(x)+log(4)$ ?

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