How do you simplify $logx^2-logxy+4logy$ ?

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Answer 1 · 2016-07-15T16:11:45

$log ((x^2 y^4)/(xy))$

$logx^2-logxy+4logy$

3 log terms can be written as the log of a single term.

If logs are added, then the numbers are multiplied.
If logs are subtracted, then the numbers are divided.

$logx^2-logxy+4logy = logx^2-logxy+logy^4$

$log ((x^2 y^4)/(xy))$

How do you simplify logx^2-logxy+4logylogx^2-logxy+4logy?