How do you solve log_3[3^(x^2-13x+28)+2/9] = log_2 5?

1 Answer
Cesareo R.
Jun 25, 2016

x =13/2 pm 1/2 sqrt[49 + (4 Log_e(3^(Log_e[20]/Log_e[2])-2))/Log_e 3]

Explanation:

log_3(3^(x^2-13x+28)+2/9)= log_2 5
3^{log_3(3^(x^2-13x+28)+2/9)}=3^{ log_2 5}
3^{x^2-13x+28}+2/9=3^{ log_2 5}
3^2 xx 3^{x^2-13x+28}+2=3^2 xx 3^{ log_2 5}
3^{x^2-13x+30}+2=3^{ log_2 5 + 2}
3^{x^2-13x+30}=3^{ log_2 5 + 2}-2

Solving for x

x =13/2 pm 1/2 sqrt[49 + (4 Log_e(3^(Log_e[20]/Log_e[2])-2))/Log_e 3]

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