How do you solve $2 log 3 + log x = log 36$ ?

Question

3840 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-07T16:38:36

See solution below.

We can start the solving process by using the log rule $blogn = logn^b$

$log9 + logx - log36 = 0$

Using the property $log_an + log_am = log_a(n xx m)$ and $log_an - log_am = log_a(n/m)$ we can continue the solving process.

$log((9 xx x)/36)$ = 0

Convert to exponential form

$(9x) / 36 = 10^0$

9x = $1 xx 36$

x = 4

Hopefully this helps!

How do you solve 2 log 3 + log x = log 36 2 log 3 + log x = log 36?