How do you condense $2 log x - 3 log y$ ?

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Answer 1 · 2016-08-07T18:19:54

$log(x^2/y^3)$

If two log terms are subtracted, the numbers are being divided.

$2logx - 3logy = logx^2 - logy^3" power law"$

= $log(x^2/y^3)$

How do you condense 2 log x - 3 log y2 log x - 3 log y?