Question

How do you evaluate `antilog 0.33736`?

Answer 1

The inverse of a logarithm is exponentiation with its base.

Explanation:

For example the inverse of the base 10 logarithm, (`log_10(x)`), is `10^(log_10(x))` by the definition of any inverse this always gives us x:

`10^(log_10(x)) = x`

Another example

`2^(log_2(x))=x`

Suppose that we have an equation:

`log_3(x-1) = 4`

Make both sides of the equation an exponent of the base, 3:

`3^(log_3(x-1)) = 3^4`

The left side becomes the argument within the logarithm, x -1:

`x-1 = 3^4`

The right side becomes 81:

`x-1 = 81`

Add 1 to both sides:

`x = 82`

Another example with base e:

`ln(x+2) = 2`

Make both sides and exponent of the base, e:

`e^(ln(x+2)) = e^2`

The left side becomes `x+2`:

`x+2 = e^2`

Subtract 2 from both sides:

`x = e^2-2`

I hope that this helps