How do you solve $(log_5 20^4)*(log_20 5^4)$ ?

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Answer 1 · 2016-04-09T06:09:53

$log_5(20^4)*log_20(5^4)=16$

$log_5(20^4)*log_20(5^4)$

= $log20^4/log5*log5^4/log20$

= $(4cancellog20)/cancellog5*(4cancellog5)/cancellog20$

= $4xx4=16$

How do you solve (log_5 20^4)*(log_20 5^4)(log_5 20^4)*(log_20 5^4)?