How do you condense $1/2[log_4(x+1)+2log_4(x-1)] + 6log_4x$ ?

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Answer 1 · 2016-06-04T18:08:14

It is

$1/2[log_4(x+1)+2log_4(x-1)] + 6log_4x => 1/2[log_4(x+1)+log_4(x-1)^2]+log_4x^6=> log_4[sqrt((abs(x+1))*(x-1)^2)*x^6]$

How do you condense 1/2[log_4(x+1)+2log_4(x-1)] + 6log_4x 1/2[log_4(x+1)+2log_4(x-1)] + 6log_4x ?