Question

How do you calculate `log_3(54)`?

Answer 1

`log 2/log 3 + 3=3.631`, nearly.

Explanation:

For long-term-memory:

`log_b a=log_c a/log_c b=log a/log b=ln a/ln b`

Here,

`log_3 54= log 54/log 3`

`=log(2 (3^3))/log 3=(log 2 + 3 log 3)/log 3=log 2/log 3 + 3`