How do you calculate $log_3(54)$ ?

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Answer 1 · 2016-05-14T04:49:19

$log 2/log 3 + 3=3.631$ , nearly.

For long-term-memory:

$log_b a=log_c a/log_c b=log a/log b=ln a/ln b$

Here,

$log_3 54= log 54/log 3$

$=log(2 (3^3))/log 3=(log 2 + 3 log 3)/log 3=log 2/log 3 + 3$

How do you calculate log_3(54) log_3(54)?