How do you condense $2log x + 4 log y - 2 log z$ ?

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Answer 1 · 2016-06-04T09:51:15

$log((x^2*y^4)/z^2)$

$2log x+4log y-2log z ?$

$log (x^2*y^4)-log z^2$

$log((x^2*y^4)/z^2)$

How do you condense 2log x + 4 log y - 2 log z2log x + 4 log y - 2 log z?