How do you evaluate $log 0.0081$ $log0.0081$ ?

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Answer 1 · 2016-11-25T04:39:35

$- 2.091515$ $-2.091515$ , nearly

$log (0.0081) = log ((81) (10^{- 4})) = log ((3^{4}) (10^{- 4}))$ $log(0.0081)=log ((81)(10^-4))=log ((3^4)(10^-4))$

$= 4 log 3 - 4 log 10 = 4 (log 3 - 1) = - 2.091515$ $=4 log 3-4 log 10 =4(log3-1)=-2.091515$ , nearly

= direct value, from the calculator.

How do you evaluate log0.0081log0.0081log0.0081?