How do you express $log_2 9$ in terms of common logs?

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Answer 1 · 2016-10-29T22:37:58

$log_2 9 = (log9)/(log2)$

Use the change of base formula: $log_b x = (logx)/(logb)$

Therefore, $log_2 9 = (log9)/(log2)$

How do you express log_2 9log_2 9 in terms of common logs?