How do you calculate ${log}_{3} 2$ $log_3 2$ ?

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Answer 1 · 2016-06-14T06:35:46

${log}_{3} 2 = 0.6309$ $log_3 2=0.6309$

As ${log}_{a} b \times {log}_{b} c = {log}_{a} c$ $log_abxxlog_bc=log_ac$

${log}_{b} c = \frac{{log}_{a} c}{{log}_{a} b}$ $log_bc=log_ac/log_ab$

Hence ${log}_{3} 2 = \frac{log 2}{log 3} = \frac{0.3010}{0.4771} = 0.6309$ $log_3 2=log2/log3=0.3010/0.4771=0.6309$

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