How do you solve log(x-5)=-2?

1 Answer
Jun 6, 2016

Applying the exponential on both sides.

Explanation:

Your x is in the log, so you have to remove it. The inverse operation of the log is the exponential, so you can do

log(x-5)=-2

e^(log(x-5))=e^-2

Because, as said, the exponential is the inverse of the logarithm, we have

x-5=e^-2

and finally

x=e^-2+5\approx 5.13