How do you solve $log_5 x=-3$ ?

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Answer 1 · 2016-04-13T03:19:17

$x=1/125=0.008$ .

Inversely, $x=5^(-3)=1/5^3=1/125=0.008$ .
Note that if $log_ax=b, x=a^b$ and, inversely, if $x=a^b, log_a x=b$ ..

How do you solve log_5 x=-3log_5 x=-3?