How do you solve $3^(-3x+1) = 3^(x-9)$ and find any extraneous solutions?

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Answer 1 · 2016-06-30T23:35:41

$5/2$

$3^(-3x+1) = 3^(x-9)$

$implies -3x+1 = x-9$

Or

$10 = 4x, qquad x = 5/2$

How do you solve 3^(-3x+1) = 3^(x-9)3^(-3x+1) = 3^(x-9) and find any extraneous solutions?