How do you calculate $log _10 (2)$ ?

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Answer 1 · 2018-03-10T17:43:42

$log_10(2)~~0.301$

Whenever we have a log problem like this, we can simplify using the Change of Base Property/Formula that states

$log_a(b)=(log_10(b)/log_10(a))$

Which is also equal to

$log_a(b)=ln(b)/ln(a)$ , where $ln=$ natural log

In our case, our base ( $a$ ) is equal to $10$ , and our $b$ is $2$ . Using the Change of Base Property, $log_10(2)$ is equal to:

$=log_10(2)/(log_10(10))$

$=>ln2/ln10$ (Which is the same thing as $log_10(2)$ )

Which, through evaluating with a calculator, we get:

$log_10(2)~~0.301$

How do you calculate log _10 (2)log _10 (2)?