Question

How do you evaluate `log_(3)36-log_(3)4`?

Answer 1

2

Explanation:

`color(blue)(log_ax-log_ay=log_a(x/y)`

`color(blue)(log_a a^x=x`

`log_3 36-log_3 4=log_3(36/4)=log_3 9=log_3 3^2=2`