How do you evaluate $log_(3)36-log_(3)4$ ?

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Answer 1 · 2016-04-01T15:33:19

2

$color(blue)(log_ax-log_ay=log_a(x/y)$

$color(blue)(log_a a^x=x$

$log_3 36-log_3 4=log_3(36/4)=log_3 9=log_3 3^2=2$

How do you evaluate log_(3)36-log_(3)4log_(3)36-log_(3)4?