How do you solve ${log}_{10} x = - 2$ $Log_10 x = -2$ ?

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Answer 1 · 2016-01-29T08:23:50

$x = \frac{1}{100} = 0.01$ $x=1/100=0.01$

Start with the given:
This is the logarithmic form:
${log}_{10} x = - 2$ $log_10 x=-2$

Convert this to exponential form:

$10^{- 2} = x$ $10^-2=x$

$x = \frac{1}{10^{2}}$ $x=1/10^2$

$x = \frac{1}{100}$ $x=1/100$

$x = 0.01$ $x=0.01$

Have a nice day !!! from the Philippines.

How do you solve log10x=−2Log_10 x = -2?