How do you expand $log x (x^2+1)^(-.5)$ ?

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Answer 1 · 2016-03-10T22:15:14

$logx-0.5log(x^2+1)$

$logx+log(x^2+1)^-0.5$ -> use property $log_bxy=log_bx+log_by$
$logx-0.5log(x^2+1)$ ->use property $log_bx^n =n*log_bx$

How do you expand log x (x^2+1)^(-.5) log x (x^2+1)^(-.5)?