How do you solve ${log}_{9} x = 1.5$ $log_9 x = 1.5$ ?

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Answer 1 · 2016-09-02T10:54:11

$:. x=27$ .

By Defn., $log_b a=m iff a=b^m$ .

$:. log_9 x=1.5 rArr 9^(1.5)=x$

$:. x=(3^2)^(1.5)$

$:. x=3^(2xx1.5)$ .

$;. x=3^3$ .

$:. x=27$ .

How do you solve log_9 x = 1.5log9x=1.5log_9 x = 1.5?