How do you condense 5 log_ (b) x + 6 log _(b) y?

1 Answer
Jul 27, 2016

log_b (x^5y^6)

Explanation:

Since nlog_b a=log_b a^n,

then

5log_b x+6log_b y=log_bx^5+log_by^6

Since

logx+logy=log(xy),

then

log_bx^5+log_by^6=log_b (x^5y^6)