How do you calculate $Log_9 49$ ?

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Answer 1 · 2016-06-01T14:26:37

$y = log_3 7$

We know that $y = log_9 49 equiv 9^y = 49$

Supposing you have for computational purposes the function

$log_b$ , with $b$ the basis, you can proceed as
$log_b 9^y = log_b 49->y log_b 9 = log_b 49$

solving for $y$

$y = (log_b 49)/(log_b 9) = (log_b 7^2)/(log_b 3^2) = (log_b 7)/(log_b 3)$ .

If you choose $b = 3$ as basis then the result will read

$y = log_3 7$

How do you calculate Log_9 49Log_9 49?